2c^2+24=14c

Solution for 2c^2+24=14c equation:

2c^2+24=14c

We move all terms to the left:

2c^2+24-(14c)=0

a = 2; b = -14; c = +24;
Δ = b2-4ac
Δ = -142-4·2·24
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*2}=\frac{12}{4}
=3
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*2}=\frac{16}{4}
=4
$